An airplane flies from Chicago to New Orleans (a distance of 1500 km) in the mor

Question

An airplane flies from Chicago to New Orleans (a distance of 1500 km) in the morning, then immediately returns to Chicago. The speed of the plane relative to the air is 237 m/s. The wind is blowing at 50 m/s from west to east, so it is perpendicular to the line that connects the two cities.

(a) What is the average speed of the plane relative to the ground on the way to New Orleans?

(b) What is the average speed relative to the ground on the way back to Chicago?

(c) What is the average speed for the entire trip?

Explanation / Answer

Given Distance from Chicago to New Orleans = 1500 km The speed of the plane relative to the air is 231 m/s. The wind is blowing at 50 m/s a)Average speed = v(231 m/s)^2 +(50 m/s)^2                          = 236.35 m/s b) Average speed = v(231 m/s)^2 +(50 m/s)^2                          = 236.35 m/s [since for speed we donot consider direction]                          = 236.35 m/s [since for speed we donot consider direction] c)Average speed for the entire trip will be 236.35 m/s Average velocity will be zero since the displacement is zero as the initial and final points are same

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