Express I as a function of the EMFs of the batteries, E and E\', and their inter

Question

Express I as a function of the EMFs of the batteries, E and E', and their internal resistances, r and r' for circuit (a).

Do the same for circuit (b)

Assuming r=r', and using your value for the interanl resistance (-1.13), calculate I for circuit A when E-E'=.5V; how much heat is created in each battery in a duration of a minute.

Assuming r=r', and using your value for the interanl resistance (-1.13), calculate I for circuit B when E=E'=1.5V; how much heat is created in each battery in a duration of a minute.

Explanation / Answer

A) total emf=E-E' total resistance=r+r' i=emf/r =>i=(E-E')/(r+r') for r=r'=1.13 ohm and (E-E')=0.5 i=(E-E')/(r+r') =0.5/(2*1.13)=0.221 A heat produced=i^2*r*t t=60s =0.221*0.221*1.13*60=0.0552*60 =3.3j B) total emf=E+E' total resistance=r+r' i=emf/r =>i=(E+E')/(r+r') for r=r'=1.13 ohm and E=E'=1.5 i=(E+E')/(r+r') =2*1.5/(2*1.13)=1.327 A heat produced=i^2*r*t t=60s =1.327*1.327*1.13*60=119.4j

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