One end of a massless coil spring is suspended from a rigid ceiling. It is found

Question

One end of a massless coil spring is suspended from a rigid ceiling. It is found that when a 3.8 kg mass is suspended from it the spring stretches 90 mm when the mass comes to rest.
(a) What is the spring constant for the spring?
N/m

(b) If the mass is then pulled down an additional 245 mm (by hand) and released from rest at that point, what will be the speed of the mass when it passes through the spring-mass rest position (this is where the spring was stretched 100.mm by the stationary mass).
m/s

I have part a I really need part B! will give lifesaver to whoever answers part b thanks

Explanation / Answer

k = mg/x = 3.8 * 9.81/.09 = 414.2 N/m b) equating energy in initial and spring mass rest position (conservation of energy) (1/2)*m*(0)^2 + (1/2)*k*x^2 = (1/2)*m*v^2 + (1/2) *k*(.1)^2 ? v^2 = (k/m)*(.245^2 - .1^2) = 5.4527 ?v = 2.335 m/s

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