A fireworks rocket is launched vertically (+y-direction) into the night sky with

Question

A fireworks rocket is launched vertically (+y-direction) into the night sky with an initial speed of 43.5 m/s. The rocket coasts after being launched, then explodes and breaks into two pieces of equal mass 2.38 s later.
(a) If each piece follows a trajectory that is initially at 46.0° to the vertical, what was their speed immediately after the explosion?


m/s

(b) What is the velocity of the rocket's center of mass before and after the explosion?
( m/s) y-direction

(c) What is the acceleration of the rocket's center of mass before and after the explosion?
( m/s2) y-direction

Explanation / Answer

by conservation of momentum,
2mv*cos46 = 2m*(43.5 - 9.8*2.38)
so, v = 29.04 m/s

 

velocity before and after explosion = 43.5 - 9.8*2.38 = 20.18 m/s 

acceleration before and after = 9.8 m/s2

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