When a crate is pushed at speed v across a smooth floor with a low coefficient o

Question

When a crate is pushed at speed v across a smooth floor with a low coefficient of friction, it has a kinetic energy KE1. When the same crate is pushed at the same speed across a rough floor with a higher coefficient of friction, its kinetic energy is KE2. What is the relationship between KE1 and KE2?

A) KE1 > KE2

B) KE1 < KE2

C) KE1= KE2

D) Impossible to determine on the basis of the information given

Explanation / Answer

more energy lost in frictional floor so kE final must decrease so Ke1>ke2 also evident from Wall= change in KE Wforce-Wfriction= kEf-KEi as in second case Wfriction comes into action kEf must decrease in second case

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