Make sure to state the folllwing: • Genetic hypothesis • Null hypothesis • Work

Question

Make sure to state the folllwing: • Genetic hypothesis • Null hypothesis • Work abs Calculations to calculate X2c • The critical value: X2 T, p, d, f
Please show in complete detail Tall yellow-flowered crocus is mated with short white flowered crocus. Both varieties are true breeding. All the F1 plants are backcrossed with the short white-flowered variety. This backcross yielded 234 tall yellow, 203 tall white, 175 short yellow, and 188 short white plants. Test and explain if the observed results fit the genetic hypothesis of 1:1:1: segregation as assessed by a X2 test? Make sure to state the following: - Genetic Hypothesis - Null Hypothesis -Work and calculations to calculate -The critical value: pdf

Explanation / Answer

Answer:

Based on the given information:

Punnett square for this cross is:

The Phenotypic ratio obtained is 1:1:1:1

Null Hypothesis: The phenotypic ratio is 1:1:1:1 as expected in Mendelian segregation

Alternative Hypothesis: The phenotypic ratio is different from 1:1:1:1

The Chi square test can be performed as below:

Population size = 234 + 203 + 175 + 188 = 800

Since the phenotypic ratio is 1:1:1:1, therefore expected frequency of all phenotypes is: 800/4 = 200

Degree of freedom = number of categories - 1 = 4 - 1 = 3

Probability value corresponding to a Chi square value of 9.67 with 3 degree of freedom is P = 0.02159. The result is significant at p < 0.05.

The critical value of Chi square for significance level 0.05 is 7.8147

Therefore, the Null Hypothesis is rejected. Based on the evidence, observed frequency is different from expected frequency.

ty ty ty ty Phenotype TY TtYy TtYy TtYy TtYy Tall Yellow Ty Ttyy Ttyy Ttyy Ttyy Tall White tY ttYy ttYy ttYy ttYy Short Yellow ty ttyy ttyy ttyy ttyy Short White

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