Two boxes of mass 6.00 and 3.00 kg are in contact and are accelerated across a h

Question

Two boxes of mass 6.00 and 3.00 kg are in contact and are accelerated across a horizontal surface by an force of 27.32 N applied parallel to the surface and pushing on the lighter box. The magnitude of the frictional force between the surface and the lighter mass is 3.97 N and between the surface and the heavier mass is 12.35 N. Find the acceleration of the two boxes.

Find the magnitude of the force exerted by the lighter box on the heavier box in the previous problem.

What is the magnitude of the force exerted by the heavier box on the lighter box.

Explanation / Answer

equation of motion for the system

F - f1 - f2 = ma

27.32 - 3.97 - 12.35 = (3 + 6)a

a = 1.22m/s2

force exerted on the heavier box by lighter box F1

equation of motion for heavier box

F1 - f2 = m(heavier)a

F1 - 12.35 = 6*1.22

F1 = 19.67N

by newton's third law of motion the force exerted by lighter box on the heavier box is equals the force exerted by heavier box on lighter box but opposite in direction

F2 = -F1

F2 = -19.67N

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.