A 100 g ball moving to the right at 4.0 m/s collides head-on with a 200 g ball t
ID: 1978640 • Letter: A
Question
A 100 g ball moving to the right at 4.0 m/s collides head-on with a 200 g ball that is moving to the left at 3.0 m/s.A)If the collision is perfectly elastic, what are the speeds of each ball after the collision? V fx 1
B)If the collision is perfectly elastic, what are the speeds of each ball after the collision? V fx 2
c)What is the direction of 100-g ball after the collision? choose one
upward
downward
right
left
D)What is the direction of 200-g ball after the collision? choose one
Upward or downward or left or right
E)If the collision is perfectly inelastic, what is the speed of the combined balls after the collision? find Vfx
F)What is the direction of the combined balls after the collision? choose one
upward
downward
left
right
Explanation / Answer
according to the law of conservation of momentum we get (0.1 kg) v1f + (0.20 kg)v2f = (0.110 kg) (4.0 m / s) + (0.20 kg) ( - 3.0 m / s)...........(1) as the collision is elastic and head on collisions v1i + v1f = v2i+ v2f ..........(2) with the above two equations solve for v1f and v2f
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