-PART 1 - (a) If m1 = m2, will the masses have an angular acceleration? (b) Give
ID: 1978646 • Letter: #
Question
-PART 1 -
(a) If m1 = m2, will the masses have an angular acceleration?
(c) Is there a net (non-zero) torque?
-PART2-
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Explanation / Answer
solved a similar question already with different numbers.. i put the question and the answer.. hope it helps!! :) kindly rate a life saver :)
A beam is supported only at one point, called the pivot point, as shown in the diagram. A block with mass m1 sits at the left end of the beam, a distance L1 from the pivot point. A block with mass m2 sits at the right end of the beam, a distance L2 from the pivot point. L2 > L1. Calculate all torques about the pivot point, remembering that positive is anti-clockwise.
If L1 = 0.930 m, L2 = 1.00m, m1 = 4.25 kg, and m2 = 2.30 kg, what is the angular acceleration of the beam?
ANSWER:
Torque = force * perpendicular distance
Force = weight = m* 9.8
Torque left side = m1 * 9.8 * L1, anti clockwise
Torque right side = -(m2 * 9.8 * L2), clockwise
Torque = (m1 * 9.8 * L1) – -(m2 * 9.8 * L2)
If L1 = 0.930 m, L2 = 1.00m, m1 = 4.25 kg, and m2 = 2.30 kg, what is the angular acceleration of the beam?
Torque = (4.25 * 9.8 * 0.930) – (2.30 * 9.8 * 1.00) = 16.1945 (anti-clockwise)
Torque = moment of Inertia * angular acceleration
Moment of Inertia = mass * distance from pivot point
Moment of Inertia = (4.25 * 0.930) + (2.30 * 1.00) = 6.2525
16.1945 = 6.2525 *
= 16.1945 ÷ 6.2525 = 2.59 radians per second
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