a) The light from the object goes through the lens and then is reflected by the
ID: 1979039 • Letter: A
Question
a) The light from the object goes through the lens and then is reflected by the mirror. What is the position of the image produced by the mirror? Your answer should be measured relative to the origin (the position of the converging lens), with a positive distance to the right or a negative distance to the left. (Note that we are not considering what happens when the light reflected from the mirror goes back through the lens again!)
b) Calculate the height of the image produced by the mirror if the object is 1.50 cm high
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Explanation / Answer
a) 1/f = 1/di + 1/do f= 20.1 cm do= object distance = 25.1 cm 1/di = 1/20.1 - 1/25.1 ==> di = 100.9 cm since it is a converging lens and the object is between f and 2f, the image is on the right of the lens (virtual) and inverted. now do for the mirror is (L - di): do= 116.3 - 100.9 = 15.4 cm f= 10.4 cm 1/di = 1/10.4 - 1/15.4 ==> di = 32 cm since it is a concave mirror and the object is between f and 2f, the image is to the left of the mirror (real) and inverted from how it was before, so it is back right-side up. the distance of the final image from the converging lens is L-32 = 84.3 cm since the magnification is -di/do which equals -hi/ho, cross-multiplying gets us: hi = di*ho/do = 32*1.5/15.4 = 3.12 cm
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