A 0.485 kg object connected to a light spring with a spring constant of 22.5 N/m

Question

A 0.485 kg object connected to a light spring with a spring constant of 22.5 N/m oscillates on a frictionless horizontal surface.
(a) Calculate the total energy of the system and the maximum speed of the object if the amplitude of the motion is 3.00 cm.
E = J
vmax = m/s

(b) What is the velocity of the object when the displacement is 2.00 cm?
± m/s

(c) Compute the kinetic and potential energies of the system when the displacement is 2.00 cm.
KE = J
PEs = J

For what values of x is the speed of the object 0.14 m/s?
x = ± cm

Explanation / Answer

a) E=1/2x22.5x0.032=0.010125J

Vmax=sqrt(0.010125x2/0.485)=0.204m/s

b) 0.010125=1/2x22.5x0.022 +0.485v2/2

v=0.1523m/s= ke

pe=1/2x22.5x0.022=0.0045J

c) 0.010125=1/2x0.485x0.142 +1/2x22.5x2

x=0.022m

2.2cm

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