Russell’s “best initial bat speed” is 60 mph, or about 27 m/s. Suppose a basebal

Question

Russell’s “best initial bat speed” is 60 mph, or about 27 m/s.
Suppose a baseball is thrown at 90 mph (or 40 m/s), and that the bat/ball collision can be
analyzed strictly from a conservation of momentum. This is acceptable because the forces
exerted by the batter on the bat are so small, and the collision is so fast, that the behavior
of the batter during the collision is irrelevant. The mass of the baseball is 0.15 kg. The
mass of the bat is about 1 kg (about 34 oz.). How fast does the ball leave the bat under
these circumstances, and what is the farthest it can go?

Explanation / Answer

MOMENTUM WILL BE CONSERVED initial momentum=1*27 - .15*40 final momentum=.15*v initial momentum =final momentum 21=.15*v v=140 m/s and it can farthest go upto 1.27=.15*v v=180m/s

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