5. A solution of 1 M glucose (side A) is separated from a solution of 0.2 M fruc
ID: 198111 • Letter: 5
Question
5. A solution of 1 M glucose (side A) is separated from a solution of 0.2 M fructose and 0.7 M sucrose (side B) by a selectively permeable membrane. The membrane is not per- meable to the sugar molecules. A Mglucose 0.2 M fructose B 0.7 M sucrose selectively permeable membrane (T/F): State whether each of the following statements is true or false. If false, explain why a. Side A is hypotonic relative to side B. b. The net movement of water will be from side B to side A C. The net movement of water will be from side A to side B. d. Side B is hypertonic relative to side A e. There will be no net movement of water. 6. You observe plant cells under a microscope that have just been placed in an unknown solution. At first, the cells plasmolyze after a few minutes, then plasmolysis reverses and the cells appear normal. Choose the statement that best describes the unknown solute. Explain your answer. plant cell a. It is hypertonic to the plant cells, and its solute cannot cross the membranes. b. It is hypotonic to the plant cells, and its solute cannot cross the plant cell membranes c. It is isotonic to the plant cells, but its solute can cross the plant cell mem- d. It is hypertonic to the plant cells, but its solute can cross the plant cell mem- -e. It is hypotonic to the plant cells, but its solute can cross the plant cell mem branes. branes. branes.Explanation / Answer
5) A) Side A is hypotonic relative to side B.
False
B) The net movement of water will be from side B to side A.
True
C) The net movement of water will be from side A to side B.
False
D) Side B is hypertonic relative to side A.
False
E) There will be no net movement of water.
False
6) What would you conclude about the unknown solution?
D) It is hypertonic to the plant cells, but its solute can cross the plant membranes.
In hypertonic solution, first the water will move outside from the cells that occurs plasmolysis of the cell. After that, water will move inside the cell for the equilibrium of the concentration, and cell becomes normalized.
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