<p>1) A mass m = 2kg is attached to an ideal spring with k = 2000N/m. The other

Question

<p>1) A mass m = 2kg is attached to an ideal spring with k = 2000N/m. The other end <br />of the spring is attached to a fixed point. The whole system is placed in a <br />horizontal level. However there is a friction between the mass and the surface <br />with &#181;k = 0.1. The spring is stretched by 30 cm from the equilibrium position. <br /> <br />What would the amplitude of this motion be at the end of the nth cycle in terms of the given variables? Find the amplitude at the end of the 6th&#160;and 200th&#160;cycle. &#160;What would the restriction be in your equation? A harmonic oscillator never stops; its amplitude decays exponentially under the influence of a resistive force. <br />What would you change in your model to make it work?</p>

Explanation / Answer

the amplitude decreases by 4mg/k for every cycle.

so after n cycles amplitude = intial amplitude - 4nmg/k

use this to solve the required values.

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.