a) Calculate the y component of the magnetic field at the center of the square.
ID: 1982523 • Letter: A
Question
a) Calculate the y component of the magnetic field at the center of the square.
Please show all work! I will rate very well! Thanks!
The four wires that lie at the corners of a square of side a= 5.60 cm are carrying equal currents i= 2.50 A into (+) or out of (-) the page, as shown in the picture. a) Calculate the y component of the magnetic field at the center of the square. b) Calculate the x-component of the force on a 1.0-cm long piece of the lower right-hand wire, due to the other three wires. Please show all work! I will rate very well! Thanks!Explanation / Answer
a) y component at the center of the square = 4x ((oI/2R)) cos(45) = 3.57 x 10^-5 T ;R=a2/2
b) x component of the force is caused by y component mag netic field caused by other wires
= (oI/2(a2)) cos45 - (oI/2a) (+ve y direction)
= - oI/2(2a) = 4.464 x 10^-6 T
hence now the force = (ixB)L ( i is into and B is in negative y => force in +ve x ( right hand rule))
= 2.5 x 4.464x10^-6 x 10x10^-2 = 1.116 x 10^-6 N
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