An ideal gas is placed in a tall vertical cylinder with cross-sectional area A =

Question

An ideal gas is placed in a tall vertical cylinder with cross-sectional area A = 0.1 m2. A frictionless moveable piston is placed vertically into the cylinder. The mass M of the piston can be adjusted by adding (or subtracting) mass to it; the gas pressure in the jar supports the piston’s weight.
(a) Suppose the initial pressure of the gas is Pa = 0.022 atm and its temperature is Ta = 300 K and the piston is a height za = 1 meter above the bottom of the cylinder. What is the initial mass of the piston? (Ignore the air pressure outside the cylinder.)

Explanation / Answer

Mg = PA

PV = nRT

P = nRT/V

Mg = nRTA/V

V = Ah

Mg = nRTA/Ah

Mg = nRT/h --------1

Mg = mRT/hM1

M1 = mocular mass of the gas

m = mass of the gas

M = mass of piston

we dnt knw M1 and m

so take n = 1

and solve for M eqn 1

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