001 10.0 points An amusement park ride consists of a large vertical cylinder tha
ID: 1987135 • Letter: 0
Question
001 10.0 pointsAn amusement park ride consists of a large
vertical cylinder that spins about its axis fast
enough that a person inside is stuck to the
wall and does not slide down when the floor
drops away.
The acceleration of gravity is 9.8 m/s2 .
Given g = 9.8 m/s2, the coefficient µ =
0.605 of static friction between a person and
the wall, and the radius of the cylinder R =
5.4 m. For simplicity, neglect the person’s
depth and assume he or she is just a physical
point on the wall. The person’s speed is
v =
2(3.14)R)/2
where T is the rotation period of the cylinder
(the time to complete a full circle).
Find the maximum rotation period T of the
cylinder which would prevent a 69 kg person
from falling down.
Answer in units of s
Explanation / Answer
mv^2r*u=mg v is given =>T^2=(4pi^2R^3)/g =>T=25.18s is Maximum time duration
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