Real capacitors have fringing fields; the electric field is not zero outside the

Question

Real capacitors have fringing fields; the electric field is not zero outside the capacitor. Consider an air-filled parallel-plate capacitor made of square plates with sides of length 1.400 mm and separated by a distance 0.100 mm. The plates have been charged by a battery such that the top plate has charge 8.673E-13 C (and the bottom plate charge -8.673E-13 C), and the battery is then removed. What is the magnitude of the force on an electron at a distance 465 mm from the center of the capacitor along the direction normal to the plates of the capacitor?

Explanation / Answer

the capacitance of the capacitor is C = eo * A/d where eo = 8.85 * 10^-12 C^2/Nm^2,A = a^2,a = 1.400 mm = 1.400 * 10^-3 m and d = 0.100 mm = 0.100 * 10^-3 m we know that Q = C * V or V = Q/C where Q = 8.673 * 10^-13 C the potential difference is V = E * d where E is electric field or E = V/d the magnitude of force on the electron is F = E * q where q = 1.6 * 10^-19 C

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