Tiny Droplets of oil acquire a small negative charge while dropping through a va

Question

Tiny Droplets of oil acquire a small negative charge while dropping through a vacuum (pressure = 0) in an experiment. An electric field of magnitude 5.92x10^4 N/C points straight down. (a) One particular droplet is observed to remain suspended against gravity. If the mass of the droplet is 2.93x10^-15 kg, find the charge carried by the droplet. (b) Another droplet of the same mass falls 10.3 cm from rest in 0.250 s, again moving through a vacuum. Find the charge carried by the droplet.

The answer was
A] (q = -4.85 x 10-19C)
B] (q = -3.22 x 10-19C)

But I need a solution.

Explanation / Answer

from force equilibrium

Eq=mg

q= -4.85x10^-19 C

b)here

0.103=1/2ax0.25^2

a=3.296

also

mg-Eq2=ma

so q2=-3.22 x 10-19C

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