2. We mix 0.6 kg of water at a temperature of 25°C with 0.8 kg of alcohol at 30.

Question

2. We mix 0.6 kg of water at a temperature of 25°C with 0.8 kg of alcohol at 30.5°C. They come to equilibrium. (Here's some useful data: The specific heat capacity for water is 1 kcal/kg°C = 4186 J/kg°C, and for alcohol it is 0.58 kcal/kg°C = 2430 J/kg°C.)
A. Calculate the equilibrium temperature that the mixture of alcohol and water
will have.

B. What is the change in entropy (in J/K) of the system when the two are mixed?
Big Hint: This is an irreversible process, so use this formula:
?S = ?Sw + ?Sa = Mwcwln(Tf /TW) + Macaln(Tf /Ta)

3. Each end of a metal wire is in thermal contact with a different heat reservoir.
Reservoir 1 is at a temperature of 752 K, and reservoir 2 is at a temperature of
345 K. Compute the total change in entropy that occurs from the conduction of
1096 J of heat through the wire.

Explanation / Answer

?S = ?Sw + ?Sa = Mw*Cw*ln(Tf /TW) + Ma*Ca*ln(Tf /Ta) .6*4186*Ln(Tf/Tw) + .6*2430*Ln(Tf/Ta) = dS

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