(a)A simple atwood\'s machine consits of two masses conected by a string that pa

Question

(a)A simple atwood's machine consits of two masses conected by a string that passes over a pulley. Derive the formula for acceleration of the masses for general m1 and m2 and evaluate for the case m1=3.00kg and m2=4.5kg. (b) what modifications and assuptions need to be included if the rotaion of the pulley of mass M, and radius R is taken into account? if M=1.00kg and R= 3.00cm, determine the value for acceleration

Explanation / Answer

let m1>m2 m1g-T=m1*a T-m2*g=m2*a a=(m1-m2)/(m1+m2) * g m1=3 m2=4.5 a=-g/5 which means direction of accelaration is opposite to direction assumed a=g/5 and m2 going downwards and m1 upwards if rotation of pulley is taken then tension will be different moment of inertia=1/2*m*r^2=0.00045 T1-m1g=m1*a m2g-T2=m2*a and a=r*alpha

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