6. Suppose that you cross true breeding wild-tyoe fruit flies with true breeding

Question

6. Suppose that you cross true breeding wild-tyoe fruit flies with true breeding black-bodied fruit flies with no wings. Wild-type traits are always dom fruit fl es. In the F2 generation you get the following results: 179 wild-type flies; 23 black- 63 black flies with wings: 58 wild-type colored flies with no wings; and bodied wingless flies. State and test a genetic hypothesis concerning the numbers of genes and allelic interactions of this data with a chi-square test. Be sure to show all of your work! (12 points) What is the observed phenotypic ratio of the F2 generation? a. b. Conduct the chi-square test below.

Explanation / Answer

A - observed phenotype ratio is around 9:3:3:1.

B-

Chi-square value is 0.63.

There are four alleles present in the cross so the degree of freedom will be 4-1= 3.

For three degree of freedom when the p-0.05 the chi-square value is 7.84.

So our data follow the Mendel's independent assortment

Observed Expected O-E (O-E)2 (O-E)2/E wild type 179 181.6875 -2.6875 7.222656 0.039753 Black wings with wings 63 60.5625 2.4375 5.941406 0.098104 wild-type with no wings 58 60.5625 -2.5625 6.566406 0.108424 Black wings with no wings 23 20.1875 2.8125 7.910156 0.391834 Total 323 0 0.638115

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