At what rate is a 60.0 kg boy high, in 8.00 s? 48 W 75.0 W 80.0 W 735 W 4.8 KW J

Question

At what rate is a 60.0 kg boy high, in 8.00 s? 48 W 75.0 W 80.0 W 735 W 4.8 KW Justification A batter this a ball The 0.140-kg the bat 30.0 m/s in a direction perpendicular to the magnitude of the impulse delivered to the baseball? 9.80 Ns 1.40 Ns 5.60 Ns 7.00 Ns 3.50 Ns Justification Delta p = M + Delta tl = 0.140 = + (30 - 40) = 1.4 Two object of the same mass move along the same line in opposite direction. The first mass is moving with speed v. The object collide in a perfectly 6.100v in the direction of the velocity of the first mass before the collision. What was the speed of the second mass before the collision. Justification 0.900v 0.00.v 10.0v 0 800v 1.200v

Explanation / Answer

8) 10m * 60kg = 600J rate = 600/8 = 75 W ans: b) 10) since the mass is the same. m1 initial speed is v after collision is 0.1 v therefore, m2 initial speed is v - 0.1v = 0.9v ans: a)

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