factor of 12 A student slides her 80.8 kg desk across the level floor of her dor

Question

factor of 12 A student slides her 80.8 kg desk across the level floor of her dormitory room a 2.00 m at constant speed. If the coefficient of kinetic k friction between the desk and the floor is 0.400, how much work did she do? 1.57 kJ 627 J 640 J 240 J 26.7 J Justification Workdone = 80.0 kg * 2* 9.80* 0.400 = 627.2 J A potential energy function is given by U(x) = (3.00 N)x + (1.00 N/m2) x2. What is the force that is associated with this potential energy function? (-0.500 N/m2) x2 + (-1.00 N/m2) x4 (0.500 N/m2) x2 + (1.00 N/m2) x1 - 3.00 N - (1.00 N/m2) x1 3.00 N + (1.00 N/m1) x1 - 3 00 N- (1.00 N/m1) x1 Justification

Explanation / Answer

answer is C f=-dU/dx

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