A 0.400-kg object moves in a circular path with in a vertical plane as a ohm 100

Question

A 0.400-kg object moves in a circular path with in a vertical plane as a ohm 100 as length ,If the angular speed at the bottom in 8.00 .what is the object what are subject in at the bottom of the circle? 5.60 N 10.5 N 16.7 N WA N justification A 0.20-kg object is attached is a spring with contain A = 10h/m and moves with simple harmonic: motion over a horizontal frictionless surface. At the leading it is displaced from equilibrium by -0.050m. what is its acceleration? t 000 m1/2 2 40 m1/2 0.1 m/s 2 2.5 m/s 2 A 60=kg women runs up a flight of stairs having a rise of 4.0 m in a time of 4.2 s. What average power did the supply? 380 W 560 W 620 W 670 W justification

Explanation / Answer

1)Tension in the string will be a sum of the both weight of the object and from the centrifugal force it experiences. So, F = m*g + m*w^2*r = .4*9.8 + .4*(8^2)*.5 =3.92 +12.8 =16.72 2)Displacement of the spring = -.05 m Force constant of the spring = 10 mass of the object = .2 Force on the spring = -kx = -*10*-.05 = .5 N Acceleration = .5/.2 = 2.5 m/sec^2 3) Mass of the women = 60 height rised = 4 m Time taken = 4.2 sec Energy required to rise = m*g*h = 60 *9.8*4 = 3.92 Power = Energy / Time = 3.92 / 4.2 = 560 Watts I hope this answers your questions!

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