<p>Two uniform solid spheres, each with mass M=0.800 kg and radius R=0.080
ID: 1991828 • Letter: #
Question
<p>Two uniform solid spheres, each with mass M=0.800 kg and radius R=0.0800m, are connected by a short, light rod that is along a diameter of each sphere and are at rest on a horizontal tabletop. A spring with force constant k=160 N/M has one end attached to the wall and the other end attached to a frictionkless ring that passes over the rod at the center of mass of the spheres, which is midway between the centers of the two spheres. The spheres are each pulled the same distance from the wall, stretching the spring, and released. There is sufficient friction between the tabletop and the spheres for the spheres to roll without slipping as they move back and forth on the end of the spring. Calculate the period.&#160;</p>Explanation / Answer
Clearly md2x/dt2 = -kx Hence the motion is simple harmonis as it is of the above form . d2x/dt2 = -kx/m T = 2p*v(m/k) = 2p*v(1.6/160) = 0.628s
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