4. The lubber grasshopper is a very large grasshopper, and is black with red and

Question

4. The lubber grasshopper is a very large grasshopper, and is black with red and yellow stripes. Assume that red stripes are expressed from the homozygous RR genotype, yellow stripes from the homozygous rr genotype and both from the heterozygous Rr genotype. What will be the phenotypic ration of the F1 generation resulting from a cross of two grasshoppers, both with red and yellow stripes (Rr x Rr)? What would be the genotypic ration of the F1 generation? What phenotypes would be produced by crossing a grasshopper with both color stripes and one with only yellow stripes?

PLEASE give a a step by step way of figuring this out

Explanation / Answer

The Rr x Rr cross would just take a simple 2x2 punnet square.

R r
R RR Rr

r Rr rr


Phenotypic ratio is just the ratio of the physical appearance, so there would be:

1 Red striped (1/4)
2 Red and Yellow striped(1/2)
1 Yellow striped (1/4)

The genotypic ratio is the ratio of the actual genes, so :

1 RR (1/4)
2 Rr (1/2)
1 rr (1/4)

The next punnet square would look like this:

R r
r Rr rr

r Rr rr


Phenotypes of this cross would be:

2 Red and Yellow striped
2 Yellow striped

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