Two genes are located on the same chromosome and are known to be 12 map units ap

Question

Two genes are located on the same chromosome and are known to be 12 map units apart. An AABB individual was crossed with an aabb individual to produce AaBb offspring. The AaBb offspring were then crossed to aabb individuals. First, if the cross produces 1000 offspring, what are the predicted numbers of offspring with each of the four genotypes: AABB, Aabb, aaBb and aabb? Second, what would be the predicted numbers of offspring with these four genotypes if the parental generation had been AAbb and aaBB instead of AABB and aabb?

Explanation / Answer

For AaBb gametes will be in

AB 44%

ab 44%

aB 6%

Ab 6%

So the progeny will be

AaBb - 440

Aabb - 60

aaBb - 60

aabb - 440

For AAbb and aaBB parents, the F1 generation will have AaBb genotype

For AaBb gametes will be in

Ab 44%

aB 44%

AB 6%

ab 6%

So the progeny will be

AaBb - 60

Aabb - 440

aaBb - 440

aabb - 60

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