Given: Vin(-) = 4V, Vin(+) = 3V R3 = 1200ohm, Vcc = 5V ANSWER BOX: (+1)Vo = (+1)

Question

Given: Vin(-) = 4V, Vin(+) = 3V R3 = 1200ohm, Vcc = 5V ANSWER BOX: (+1)Vo = (+1) Power dissipated by R3 = Build this circuit in Multisim and create a reference voltage with 2 resistors that sets the Vin(-) voltage at 2 Volts. Use a potentiometer and one fixed resistor on the Vin(+) pin so that the voltage can be adjusted at Vin(+) from exactly 1 Volt at 0% to exactly 3 Volts at 100%. Use +Vcc as the voltage that is connected to the voltage dividers for both Vin(+) and Vin(-). Show screen shots with a probe on Vin(-), Vin(+), and Vo for the cases when the potentiometer is at 0% and 100%.

Explanation / Answer

A. open loop gain nearly 105. so in above circuit Vout=(Vin+-Vin-)*105.=-105V. it reaches saturation valve of -Vcc.

hence Vo= -5 V.

B. Power dissappated across R3 is Vo2/R = 25/1200 = 0.021W

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