The maximum stress theta_max at the edge of a hole (diameter d) in a thin plate

Question

The maximum stress theta_max at the edge of a hole (diameter d) in a thin plate with width w and thickness t, loaded F by a tensile force is given by: theta_max = K_t theta_nom where theta_nom = F/t(w-d) and K_t = 3 - 3.14 (d/w) + 3.667 (d/w)^2 - 1.527 (d/w)^3 Write a MATLAB program in a script file that calculates theta_max. The program should read the values of F, w, d, and t from an ASCII text file using the load command he output should be in the form of a paragraph combining text and numbers, i.e.- something like: "The maximum stress in a plate with a width of XX in and thickness of XXX in and a hole of XX in. in diameter, due to a tensile force of xxx lb is XXXX psi", where xx stands for numerical values. The stress should be rounded to the nearest integer. Use the program to calculate theta_max when w = 2.5 in, d = 1.375 in., t = 0.1875 in., and F = 8000 lb.

Explanation / Answer

Code:

A=load ('HW4P5DATA.txt');
w=A(1);
d=A(2);
t=A(3);
f=A(4);
sigma=f/(t*(w-d));
p=d/w;
kt=3-3.14*p+3.667*(p^2)-1.527*(p^3);
smax=sigma*kt;
round(smax);
fprintf('The maximum stress in a plate with a width of %5.4f in. and thickness of %5.4f in. and a hole of %5.4f in. diameter, due to a tensile force of %12.4f lb is %12.4f psi ',w,t,d,f,smax);
return

Result:

The maximum stress in a plate with a width of 2.5000 in.
and thickness of 0.1875 in. and a hole of 1.3750 in. diameter,
due to a tensile force of 8000.0000 lb is 80714.4439 psi

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.