What force does a trampoline have to apply to a 45.0 kg gymnast to accelerate he
ID: 1996778 • Letter: W
Question
What force does a trampoline have to apply to a 45.0 kg gymnast to accelerate her straight up at 7.50 m/s^2 Suppose that the net external force (push minus friction) exerted on a lawn mower it 51 N (about 11 lb) parallel to the ground. The mass of the mower it 24 kg. What it its acceleration? A boy pushes his sister in a sled at rate of 5 m/s^2. If the sister weighs 60 lbs and the tied weighs 25 lbs. What force is je exerting? A vertical steel beam in a building supports a load of 6.0 times 10^-4 N. If the length of the beam is 4.0 m and its cross-sectional area is 8.0 times 10^-3 m^-2, find the distance the beam is compressed along its length. A man applies a force of F = 3.00 times 10^2 N at an angle of 60 degree to the door, 2.00 m from its well-oiled hinges. Find the torque (i.e. moment) on the door. A woman of mass 55.0 kg sits on the left end of a see-saw (the plank has a length of 4.0 m). Where should a man of mass 75.0 kg sit if the system is to be balanced? A 50 kg mass is suspended from a cable with a diameter of 2.0 cm. What is the stress on the cable? A 50 m long rod is stretched by 0.1 m by a force. What is the strain on the rod? By how much does a 65.0-kg mountain climber stretch her 0.800 cm diameter nylon rope when she hangs 35.0 m below a rock outcropping? Calculate the force a 70.0-kg high jumper must exert on the ground to produce an upward acceleration 4.00 times the acceleration due gravity.Explanation / Answer
1)
F=ma
force =mass * acceleration
force=45*7.5 newton
force= 337.5 newton
3)
force=mass * acceleration
force=(mass of sister +mass of sledge)* acceleration
force=(60+25)*0.4535 kg/lbs* 5
force= 192.7375 newtons
6)
equating moments on the pivot
mass of women* distance from the pivot= mass of man* distance of man from the pivot
55*4=75*d
d=2.9m
man should sit 2.9 m from the pivot on the right side.
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