This is just one question, I HAVE ANSWERED QUESTIONS A & B, I ONLY NEED HELP WIT

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This is just one question, I HAVE ANSWERED QUESTIONS A & B, I ONLY NEED HELP WITH QUESTION 2 C,D and E. please exact answers. The University of Colorado's PhET group has a very nice simulation that allows you to explore how pressure changes in a fluid due to the effects of gravity. It's called Under Pressure, and if you click the link you can either download the sim or run it in your browser. Here's what the user interface looks like. Although it's pretty obvious, we have added notation to show you some of the controls that we are going to be referring to in this problem. turn on add liquid ruler and horiz. grid switch between air and vacuum change :- change shape planet remove liquid This is what it looks like when you run it in the browser, have turned on the ruler and the horizontal lines, and have moved the ruler so that it measures the distance below the top of the container (which is NOT necessarily the depth of the fluid). You can measure the pressure by using your mouse to grab the meter and drag it wherever you want. Note the the measurement is made at the little needle tip at the base of the meter. Be sure that your meter is set to the SI unit of pressures, Pascals(1 N/m2). The meter reports its results in kPa (kiloPascals = 1000 N/m). For this problem use g 9.80 N/kg Before you begin, turn on the grid and ruler and align the ruler as shown here to use as a coordinate system. We will report a reading on the ruler as a y coordinate

Explanation / Answer

2C) The units of pressure are in kPa or kilo pascal which is equal to 1000 N/sq.m, hence the 6 digits ae significant. The last two digits are equal to 100N/sq.m which is important, it is not positioning error.

2D) The pressure in boththe vessels would be same either 1 m below or just above the bottom because the pressure in a fluid depends only on the depth from the top and not on the shape of the vessel. The depth from the top is same and both vessel are connected at the bottom.

Pressure at 1 m below :111.2 kPa, just above the bottom 130.5 kPa

2E) The height difference between the two fluid coulmns is 1 mt. On one side we have out 1000 kg weight on the other side we have a fluid coulmn of 1 mt height which is equal to its weight. The density of the fluid is 1000 kg/m3

The volume of the acess fluid on the right side is 1 cu.m heigt is 1 m henc hence the area of the wider channel is 1 sq.m

The volume of the fluid pushed down by the narrow coulmn is eqaul to the volume of fluid raised in the wide coulmn. The wider coulmn has rasied by 0.20 m whereas the narrow coulmn has goneodwn by 0.8 m. The areas are in the ration of 0.2/0.8 = 1/4

The are of the narrow coulmn is 1/4 of the wider coulmn = 1/4 sq.m

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