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1. In order to produce a(n) 0.5 dilution, in a total volume of 10 mL, how many m

ID: 199734 • Letter: 1

Question

1. In order to produce a(n) 0.5 dilution, in a total volume of 10 mL, how many mL of sample would be required?

2. Below are three graphs each depicting the same data. The data show the change in abundance of a culture of bacteria during exponential growth.

Which of the three graphs below use a linear scale on the y-axis to depict the change in abundance?

3. Below are three graphs each depicting the same data. The data show the change in abundance of a culture of bacteria during exponential growth.

Which of the three graphs have log transformed the y-axis to plot the data in log space?

Below are three graphs each depicting the same data. The data show the change in abundance of a culture of bacteria during exponential growth.

Which of the three graphs below use a linear scale on the y-axis to depict the change in abundance?

Change in Abundance Time

Explanation / Answer

1.

0.5 dilution can refer to two types of dilution.

i. 0.5 dilution = 1/2 dilution

1 mL of stock + 1 mL of dilutant

So, for 10 mL----> 5 mL stock + 5 mL dilutant

ii. 0.5% dilution = 0.5 mL in 100 mL

0.5 mL of stock + 99.5 mL of dilutant

So, for 10 mL----> 0.05 mL stock + 9.95 mL dilutant

2.

Bacterial exhibit S-shaped growth curve. The S-shape is due to the lag phase in the initial stages.

So, the third graph represents a bacterial growth curve.

3.

Bacterial exhibit S-shaped growth curve. The exponential phase is characterized logarithmic growth. The linear extrapolation of the logarithmic line does not go through the origin.

So, the third graph represents a bacterial growth curve in the exponential phase.