An alpha particle ( ? ), which is the same as a helium-4 nucleus, is momentarily

Question

An alpha particle (?), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of ?3.45×10?3 V .

The charge and the mass of an alpha particle are q? = 3.20×10?19 C and m? = 6.68×10?27 kg , respectively.

where ?V is measured in volts. To verify that this expression for (vf)? has the correct units of velocity, you need to perform some unit analysis. Begin by finding the equivalent of a volt in terms of basic SI units. What is a volt in terms of meters (m), seconds (s), kilograms (kg), and coulombs (C)?

Express your answer using the symbols for the units meters, seconds, kilograms, and coulombs.

When I got the answer wrong by saying it was 575 m/s it said ....."the correct answer involves the variable C, which was not part of your answer."

PLEASE HELP. everyone is getting it wrong

Please show your work.

Explanation / Answer

According to the given problem,

From the definition of the Volt unit ( 1V pd = 1J of energy transferred to/from each Coulomb of charge passing between two points) ..

EPE loss = pd (J/C) x q (C) = -3.45*10-3J/C x +3.20*10-19C

U = - 1.10*10-21 J

By conservation of energy principal,

loss of electrical PE(U) = KE gained(½mv²)
1.10*10-21J = 0.5*6.68*10-27kg * v2

v = (2 x 1.10*10-21 / 6.68*10-27)

v = 575.0 m/s

B) We needs Volts in terms of m,s,kg,C

Volte = J/C = N-m/C = kg-m2/s2-C

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