Bookmarks indow Help Phys2425 Fall 2016 Assignment 20 ment Responses/submit?dep
ID: 1997797 • Letter: B
Question
Bookmarks indow Help Phys2425 Fall 2016 Assignment 20 ment Responses/submit?dep 15094330 Netflix Apple Disney ESPN Yahool Google Music Tarleton Blackboard Phys242s Fall 2016 signment 20 Simple Harmonie Motion homework Physics Forums The Fusion of Science 3. o ove points I Previous Answers HRw10 15 P014 My Notes o Ask your T A simple harmonic oscillator consists of a block of mass 3.00 kg attached to a spring of spring constant 110 NVm. When t 4.00 s, the position and velocity of the block are +0.129 m and +3.415 m/s. (a) What is the amplitude of the oscillations? X m (b) what was the position of the mass at t o s? (Indicate the direction with the sign of your answer.) (c) What was the velocity of the mass at t 0 s? (Indicate the direction with the sign of your answer.) m/s Show My Work opekonal Submit Answer Save Progress My Notes o Ask Your Teacher 4. -8 points HRW10 15 P031 constant 104 N/m. The object is dis aced from eq briurn kg object on a horizontal frictionless surface is attached to a sp with sprinExplanation / Answer
equation of motion:
x = A cos(wt + phi)
w = sqrt(k/m) = 6.06 rad/s
x = A cos(6.06t + phi)
at t = 4, x = +0.129 m
0.129 = A cos(24.24 + phi) .......(i)
v = dx/dt = - 6.06A sin(wt + phi)
3.415 = - 6.06A sin(24.24 + phi) ........(ii)
(ii) / (i)
tan(24.24 + phi) = - 4.368
24.24 + phi = 4.93 rad
(A) putting (24.24 + phi) value in (i)
0.129 = A cos(4.93)
A = 0.589 m
(B) phi = - 19.31 rad
at t = 0
x = 0.589 cos(-19.31) = 0.528 m
(c) v = - 3.57 sin(-19.31) = 1.59 m/s
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