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problem in the table refers to a different combination of lenses and different v

ID: 1997822 • Letter: P

Question

problem in the table refers to a different combination of lenses and different values for distances, which are given in centimeters. The type of lens is indicated by C for converging and D for diverging; the number after Cor Dis the distance between a lens and either of its focal points (the proper sign of the focal distance is not indicated). Find (a) the image distance iz for the image produced by lens 2 (the final image produced by the system) and (b) the overall lateral magnification M for the system including signs. Also, determine whether the final image is (c) real or virtual, (d) inverted from object o or noninverted, and (e) on the same side of lens 2 as object o or on the opposite side (a) (b) (c) (d) (e) Lens 1 d Lens 2 R/V I/NI Side p1 C, 19 12 C, 9.3 +20 Units Tcm (a) Numbe 19.526 (b) Numbe 0.46 Unit This answer has no units (c) rea

Explanation / Answer

for lens1:

f1 = +19 cm

p1 = +20 cm

Appying lens equation,

1/f1 = 1/p1 + 1/q1

q1 = p1 f1 / (p1 - f1) = 380 cm

now for lens 2:

f2 = + 9.3 cm

image by lens 1 will work as object for lens 2.

p2 = 12 - 380 = - 368 cm


1/9.3 = 1/(-368) + 1/q2


q2 = - 9.071 cm


(A)distance of final image from lens 2 = 9.071 cm

(B) M = (-q1/p1)(q2/p2)

= (380/20) (-9.071/-368)

= 0.468


(c) Real

(D) M is positive hence non-inverted.