Problem 2: An inductor has N 950 turns. When the current going through it is I 0

Question

Problem 2: An inductor has N 950 turns. When the current going through it is I 0.44 A, the magnetic flux through one coil is P 7.5 T m The current is then changed to In 0.82 A in 4t 2.5 s. Randomized Variables N 950 0.44 A Dtheexpertta com 75 T m II 0.82 A 4t 2.5 Part (a) Express the inductance Lin terms of N, Iand p Expression Select from the variables below to write your expression. Note that all variables may not be required. a, B, At, Y, D, e, d, g, h, I, L, m, N, P, t Part (b) Calculate the numerical value of L in H. Numeric A numeric value is expected and not an expression. Part (c) Express the magnitude of the induced emf in terms of L, I, II, and 4t. Expression Select from the variables below to write your expression. Note that all variables may not be required. a, B, At, Y, D, 0, d, g, h, I, Ii, L, m, n, P Part (d) Calculate the numerical value of E in V Numeric A numeric value is expected and not an expression.

Explanation / Answer

Here ,

N = 950

I = 0.44 A

flux = 7.5 T.m^2

I1 = 0.82 A , t = 2.5 s

a) for the inducance

Inductance = Total flux/current

L = N * /I

part b)

L = 950 * 7.5/(0.44)

L = 16193 H

the inductance of coil is 16193 H

part c)

for the induced emf

induced emf = L * (I1 - I)/t

the induced emf is L * (I1 - I)/t

part d)

for the value of E

E = 16193 * (0.82 - 0.44)/(2.5)

E = 2461.3 V

induced emf is 2461.3 V

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