A 0.12 kg baseball is dropped from rest from a height of 2.0 m above the ground.

Question

A 0.12 kg baseball is dropped from rest from a height of 2.0 m above the ground. What is the magnitude of its momentum when it is at a height of 1.0 m above the ground? 0.75 kg middot m/s 0.53 kg middot m/s 2.4 kg middot m/s 4.4 kg middot m/s 0.062 kg middot m/s A 500 kg cannon fires a 4.0 kg projectile with a velocity of 250 m/s relative to the ground. What is the recoil speed of the cannon? 1.0 m/s 2.0 m/s 4.0 m/s 8.0 m/s 16 m/s A car stopped at a traffic light is rear-ended by a pickup truck. Their bumpers become entangled and they move off together after the collision. During the collision: Momentum is conserved. Kinetic energy is conserved. Mechanical energy is conserved. Both A and B are true. None of the above are true. A hoop of radius 0.50 m and a mass of 0.20 kg is released from rest and allowed to roll down an inclined plane. How fast is it moving if the elevated end is 3.0 m? 2.2 m/s 3.8 m/s 5.4 m/s 6.26 m/s 7.7 m/s 14.7 m/s

Explanation / Answer

7)

for the magnitude of momentum

magnitude of momentum = m * sqrt(2 * g * h)

magnitude of momentum = 0.12 * sqrt(2 * 9.8 * (2 - 1))

magnitude of momentum = 0.531 Kg.m/s

option (B)

10)

let the recoil speed is vf

500 * vf - 4 * 250 = 0

vf = 2 m/s

option (B)

11)

as during the collision , there is no external force acting on the truck and car

A) Momentum is conserved

12)

let the final speed is vf

m * g * h = 0.5 * m * v^2 + 0.5 * I * w^2

m * g * h = 0.5 * m * v^2 + 0.5 * m * r^2 * (v/r)^2

9.8 * 3 = v^2

v = 5.4 m/s
option (C)

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