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NAME: PHYSICS 235 TEST 2 DATE: FALL, 2016 Average Speed total distance total tim

ID: 1998545 • Letter: N

Question

NAME: PHYSICS 235 TEST 2 DATE: FALL, 2016 Average Speed total distance total time Average velocity total displacement/total time AVAt G-6.67 v 10 N m kg' Vi at g 9.8 m/s M, 5.98 x 10" kg AX Vi t a t RE 6,4 x 10 m NA 6.02 x 10 /mole 2 a 400 2, a AX R 8.31 J/mole-K F.et m aart k 1.38 x 101 J/K W (work) F d Cos 0 P (power) W /t W.et KE KE. work-energy theorem I atm .01 x 10' Pa 1 gm/cm'- 10' kg/ m' P.E K.Er P.Er frd K.Ei AK.E P (momentum MV J (impulse)- F At AP Xom (mi xi m: x: y m, m. Conservation of momentum: M, vut M. V M Virt. M. V Via V Elastic collision: at ra UG -GM m/r

Explanation / Answer

let the 3kg block go down with acceleration a

writing the force equations we have

3g - T = 3a ------(1)

T - 0.3*5g = 5a ------(2)

adding both equations we have

4.5g = 8a

a = 5.5125 m/s2

T = 3(g-a)

= 3(9.8-5.5125)

= 12.8625 N