Consider a pendulum which consists of a small metal ball of mass m = 0.15 kilogr

Question

Consider a pendulum which consists of a small metal ball of mass m = 0.15 kilograms, suspended by a nearly massless string. The ball is raised to a height h = 0.25 meter above the lowest point and released from the rest (with its string) A) What is its kinetic energy at the moment of the release? B) How much larger is the gravitational potential energy at the moment of release then at the lowest point? C) What is the kinetic energy of the pendulum at the lowest point? D) What is the speed of the pendulum at the lowest?

Explanation / Answer

mass of the ball m = 0.15 kg

Raising height h = 0.25 m

(A). Kinetic energy at the moment of the release K = 0

Since at the time of moment speed of the ball is zero.

(B).Gravitational potential energy at the time of release with respect to the lowest point U = mgh

U = (0.15)(9.8)(0.25)

= 0.3675 J

(C).Kinetic energy at the lowest point K ' = U Since from law of conservation of energy.

K ' = 0.3675 J

(D). We know K ' = (1/2)mv 2

From this v = (2K ' /m)1/2

= [(2x0.3675)/0.15]1/2

= 2.213 m/s

Speed of the pendulum at the lowest point v = 2.213 m/s

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.