Question 1. Prove this mathematically: let y1 and y2 be their displacements, and

Question

Question 1.

Prove this mathematically: let y1 and y2 be their displacements, and the distance between them delta y21=y2-y1. use a kinematic equation y=y0+v0t+1/2 a t for both, and subtract them from each other. Note that t will be the same for both, and that they both have no initial velocity. Is any term left over after subtraction? if so, would it change with time?

Question 2. If two objects are dropped from the same height, but at diffrent times. Does the distance btween them change as they drop? if so how?

Explanation / Answer

1)

time taken is t

initial velocity is v0 = 0 m/s

then y1 = y01 +(0*t) + (1/2)*a1*t^2 = y01 + (1/2)*a1*t^2

y2 = y02 + (1/2)*a2*t^2

(y2 - y1) = (y02-y01) + (1/2)*(a2-a1)*t^2

the difference change with time as (y2 - y1) = (y02-y01) + (1/2)*(a2-a1)*t^2

2) after 1 sec

distance between them is S = (Vo*t)+(0.5*a*t^2)

taking initial velocity Vo = 0 m/s

a = g and t2-t1 = 1

S2-S1 = (0.5*9.81*(t2-t1)^2)

S1 = 4.905*1^2 = 4.905 m

after 2 sec

S2-S1 = (0.5*9.81*2^2) = 19.62 m

yes changes and the change in distance is directly proportional to the square of the time t

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.