You are standing near a building and throw a ball straight up with an initial sp

Question

You are standing near a building and throw a ball straight up with an initial speed of v. The ball rises to a highest point at half the building's height. You now wish to throw the ball so that it just rises to the top of the building. What should be the initial speed of the ball in the second case? A ball is shot vertically upward from the surface of a planet in a distant solar system. The acceleration due to gravity on this planet is not known, but can be figured out from the observation that the ball reaches a maximum height of 25 m and 'remains in the air' (for its complete up and down motion) for 5 seconds. What is the magnitude of the acceleration due to gravity on this planet? What is the magnitude of the initial velocity of the ball? A ball falls from rest from the top of a building and passes a window 1.5 meters high in 0.1 second. How far above the top of the window did the ball start to fall?

Explanation / Answer

a) given

h/2 = v^2/2g

h = 2v^2/2g

let V1 be the ne velocity

V12/2g =  2v^2/2g

V1= 1.414 V

b)

time of flighth= 2u/g = 5

maximum heught = u^2/2g = 25

from above eqautions eh have

u/4 = 5

u = 20 m/sec

u = 20m/sec

and acceleration due to gravity

g = 8 m/sec^2

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