AM Inbox 778) jacob h X O Grant@Heart-Logi x Bb Experiment 1 Melt x N Netflix X

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AM Inbox 778) jacob h X O Grant@Heart-Logi x Bb Experiment 1 Melt x N Netflix X a lmmunology Made R x University of Connec x Jacob C fi WWW. Saplinglea rning com /ibiscms/mod/ibis/view.php?id-2469877 EE Apps UCHC idate Sel... 8 one card office D This week's M O Best Medical School... IBb My courses Black University of Conne... P MyLab & Mastering 26/2016 11:00 PM A 41.5/100 Assignment Information Gradebook Attempts Score Print Calculator Periodic Table Available From 8/2016 06:00 PM 00 Questi 9 of 12 26/2016 11:00 PM Due Date Map Points Possible 100 98 Grade Category: Graded A large positively charged object with charge q 4.25 AMC is brought near a negatively-charged plastic ball suspended from a string of negligible mass. The suspended ball has a charge of q- 49.3 nC and a Description: 00 mass of 16.5 grams. What is the angle the string makes with the vertical when the positively charged Policies: object is 17,5 cm from the suspended ball? The positively-charged object is at the same height as the Homework suspended ball. 00 heck y Number plete up on any question You can keep trying to answer each question until 00 you get it right or give up. 5% e points available t ct att O eTextbook o Help With This Topic Web Help & Videos O Technical Support and Bug Reports Previous Give Up & View Solution Check Answer Next Exit 9:57 PM /25/2016

Explanation / Answer

here,

hanging charge , q1 = - 49.3 * 10^-9 C

q2 = 4.25 * 10^-6 C

distance , x = 0.175 m

the net force of attraction, F= k * q1 * q2 /x^2

F = 9 * 10^9 * 49.3 * 10^-9 * 4.25 * 10^-6 /( 0.175)^2

F = 0.06157 N

let the tension in the string be t and the angle be theta

t * cos(theta) = m * g ...(1)

and

t * sin(theta) = F.....(2)

from (1) and (2)

tan(theta) = F/mg

theta = arctan( 0.06157 /( 0.0165 * 9.8))

theta = 20.85 degree

the angle with the verticle is 20.85 degree

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