8-1. Please show work. Near the end of a marathon race, the first two runners ar

Question

8-1. Please show work.

Near the end of a marathon race, the first two runners are separated by a distance of 45.0 m. The front runner has a velocity of 3.50 m/s, and the second a velocity of 4.25 m/s. (a) What is the velocity of the second runner relative to the first? 0.75 m/s faster than the front runner. (b) If the front runner is 250 m from the finish line, who will win the race, assuming they run at constant velocity? The second runner will win. O The first runner will win. (c) What distance ahead will the winner be when she crosses the finish line? 53.33

Explanation / Answer

for

A) ans B) answers were already sloved

c) need to calculate

time, t= distance / velocity

Write distance = V*t for each runner and then solve for the time:
first runner :3.5xt = 250 => t = 250/3.50 = 71.43s
second runner: 4.25xt = 250+45 = 295 => t = 295/4.25 = 69.41s
So the second runner will over take the first and win by 71.43-69.41 = 2.02s

Now

distance = time x velocity = 2.02 x 3.50 =7.07m ahead will finish the winner

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