hello, Can anyone help for these questions? Three charged particles are located

Question

hello,

Can anyone help for these questions?

Three charged particles are located at the corners of an equilateral triangle as shown in the figure below (let q - 1.00 pC, and L 0.350 m). Calculate the total electric 7.00-pC charge. Two identical conducting small spheres are placed with their centers 0.285 m apart. One is given a charge of 12.0 nC and the other a charge of 16.0 nC. Find the electric force exerted by one sphere on the other. The spheres are connected by a conducting wire Find the electric force each exerts on the other after they have come to equilibrium

Explanation / Answer

F = F1+F2

Fx = F1x + F2x

Fy = F1y+F2y

F1x = 9*10^9*1*7*10^-12*cos 60 deg/(0.35^2) = 0.2571 N

F2x = 9*10^9*4*7*10^-12*cos 60 deg/(0.35^2) = 1.028 N

F1y = 9*10^9*1*7*10^-12*sin 60 deg/(0.35^2) = 0.445 N

F2y = 9*10^9*4*7*10^-12*sin 60 deg/(0.35^2) = 1.781 N

Fy = 0.445 - 1.781 = -1.336 N

F = (Fx^2 +Fy^2)^0.5 = (1.2851^2 + 1.336^2)^.5 = 1.853 N

final answer is 1.853 N

2)

.(a) F = 12*10^-9*16*10^-9*9*10^9/0.285^2 = 21.274*10^-6N away from other sphere

(b)F = 14*10^-9*14*10^-9*9*10^9/0.285^2 = 21.717*10^-6N away from other sphere

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