Using the same triangle, fine the vector components of the electric force on q1
ID: 2001183 • Letter: U
Question
Using the same triangle, fine the vector components of the electric force on q1 and the vector's magnitude and directions. (Use the charges give in the practice it section).
Given: q1= 6.09x10^-9 C q2= -2.04x10^-9 C q3= 5.20x10^-9 C
Fx= ____ N Fy= ____ N Magnitude= _____ N Direction= _____ degrees counterclockwise from x+ axis A Charge Triangle ulomb's sions. 4.00m sider ges at the ngle, as ure, 5.00 m 5.00 m The force exerted by q1 on 43 is F13. The force exerted by 92 on q3 is F23. The resaltant One exerted on 93 is the vector sum F13 + F23 x 10-9 c -9 C, and C. (a) Find the components of the force iF on q3. (b) Find the components of the ,
Explanation / Answer
Look at the picture :
Fa = F12 = kq1*q2/r12^2 = 9 x 10^9 * 6.09 10^ -9 * -2.04x10^-9 C/3^2
= 1.24x 10^-8 N
Fb = F13 = kq1*q3/r13^2 = 9 x 10^9 * 6.09 10^ -9 * 5.20x10^-9 C/3^2
= 3.16 x 10^-8N
a) Fx = Fax + Fbx
= 1.24x 10^-8 cos 90 + 3.16 x 10^-8 cos 37
= 0 + 9.5 x 10^-8 =2.52 x 10^-8 N
b) Fy = Fay + Fby
= 1.24 x 10^-8 sin 90 + 3.16 x 10^-8 sin 37
=3.14 x 10^-8 N
c) R = (Fx^2 + Fy^2)
= (2.52 x 10^-8^2 + 3.14 x 10^-8 ^2)
= 4.02 x 10^-8 N
d) tan = Fy/Fx
= arc tan (3.14 x 10^-8 / 2.52*10^-8)
=51.11 degrees
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