Suppose you want to determine the electric field in a certain region of space. Y

Question

Suppose you want to determine the electric field in a certain region of space. You have a small object of known charge and an instrument that measures the magnitude and direction of the force exerted on the object by the electric field. (a) The object has a charge of +35.0 C and the instrument indicates that the electric force exerted on it is 50.0 N, due east. What are the magnitude and direction of the electric field? E = (b) What are the magnitude and direction of the electric field if the object has a charge of -30.0 C and the instrument indicates that the force is 40.0 N, due west? E =

Explanation / Answer

the relation between eectric field (E) and electric force(F) is given by F = Eq

where q is charge

part A : E = F/q = 50 *10^-6/35 * 10^-6

E = 50/35

E = 1.428 N/C , this is towards east

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part B:

E = F/q

E = 40 *10^-6/(-30*10^-6)

E = -1.334 N/C

this is towards opposite of west = east again

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