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The figure bellows shows two parallel plates. Assume they are infinite in area (

ID: 2001886 • Letter: T

Question

The figure bellows shows two parallel plates. Assume they are infinite in area (this way we can neglect edge effects). The plate on the left is at a potential of +56V and the plate on the right is at a potential of OV. The plates are a distance 28cm apart and the dashed lines are spaced equally 7cm apart. Evaluate the following statements appropriately: The electric potential energy of an electron at point A is_the electric potential energy of an electron at point B. The electric potential at point C is_the electric potential at point F. The electric potential energy of a proton at point A is_the electric potential energy of an proton at point C. The electric potential at point C is_the electric potential at point A. What is the electric potential at point A? What is the magnitude of the electric field at point C?

Explanation / Answer

change in potential energy is U2-U1 = q*(V1-V2)

So the electric potential energy of an electron at point A is larger than the the electric potential energy of an electron at point B

the elctric potential at point C is equal to the electric potential at point F


the electric potential energy of an electron at point A is larger than the the electric potential energy of an electron at point C

the elctric potential at point C is less than the electric potential at point A

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Electric potential at A is VA

then (56-0)/28 = (56-VA)/7

VA = 42 V

electric potential at C is VC

(56-0)/28 = (56-VC)/21

56- VC = 42

VC = 56-42= 14 V

then Electric field at C is (VC-VA)/d = (42-14)/(0.14) = 200 N/C

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