Two tuning forks are both rated at 264 Hz, but when they are struck at the same

Question

Two tuning forks are both rated at 264 Hz, but when they are struck at the same time, a beat frequency of 4.00 Hz is created. If you know that one of the tuning forks is in tune (but you are not sure which one), what are the possible values of the "out-of-tune" fork? Find the smallest value. (Express your answer to three singificant figures.) 2) If you know that one of the tuning forks is in tune (but you are not sure which one), what are the possible values of the "out-of-tune" fork? Find the largest value. (Express your answer to three singificant figures.)

Explanation / Answer

The beat frequency is always equal to the difference in frequency of the two notes that interfere to produce the beats.
Beat Frequency = 4.0 Hz

Therefore, possible values of the "out-of-tune" fork -

Smallest Value = 264 - 4 = 260 Hz
Largest Value = 264 + 4 = 268 Hz

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.