please explain the solution. A solid rectangular bar of iron has a size of L = 1
ID: 2002361 • Letter: P
Question
please explain the solution.
A solid rectangular bar of iron has a size of L = 10.50 inches, W= 3.175 cm, and H = 0.15 ft. lron has a density p approximate equalto 7.874 g/cm^3 at near room temperature. Perform the following calculations to the correct number of significant figures. You must show your conversion factors to get full credit. What is the surface area (in square inches) of the bar What is the volume (in mm 3) of the bar What is the mass (in kg) of the bar If the local gravitational constant g has the value 9.81 m/s 2, what is the bar's weight (in newtons)Explanation / Answer
L =10.5 inches = 266.7 mm
W = 3.175 cm = 31.75 mm
H = 0.15 ft = 45.72 mm
1) Surface Area = 2* (LW+LH+WH)
Surface Area = 2*( 266.7*31.75+31.75*45.72+266.7*45.72)
Surface Area = 44225.718 mm^2 = 44225.718*0.0393701^2 square inch = 68.55 square inch
2)
Volume = LWH
Volume = 266.7*31.75*45.72
Volume = 387144.3 mm^3
3)
Mass = density*volume = (7.874*10^-3 / 10^3 )* 387144.3 = 3.04 Kg
4)
Weight = mg
weight = 3.04*9.81 = 29.9 N
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